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Transcript

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00:00 - 00:59 | everyone never question to solve question is find the maximum and minimum values of trigonometric expression sin theta minus cos theta + 1 since since the expression is expression is sin theta minus cos theta + 1 it is having a constant term then let FX is a sin x + b cos x in that case in that case equals to our |

01:00 - 01:59 | cos theta = 2 Sin Theta square square = square cos square theta in b square equal to R square sin square theta so a square + b square is equal to Ara square sin square theta + cos square theta it would be a square + b square equal or we can say that are two plus minus under root of a square + b square for the expression A cos theta + sin theta we have maximum value a square + b square and root and minimum value is square + b square negative under root 2 in that case in that case since |

02:00 - 02:59 | sin x + theta is less than or equal to 1 therefore therefore sin theta minus cos theta + 1 is under root of 1 + 11 square + 1 X square + 1 then this is the maximum value and it would be root 2 + 1 now for minimum value it would be negative of a square + Y square + 1 so that will become minus root 2 + 1 |

03:00 - 03:59 | maximum value of theta minus cos theta + 1 is 1 + root 2 while minimum value is sin theta minus cos theta + 1 is 1 minus root 2 this is our final answer I hope you understood thank you |